If I = \(\int_0^{\pi / 4}\) x2 cos2x dx then

1
\(\frac{\pi^2}{32}\) + \(\frac{1}{4}\)
2
\(\)\(\frac{\pi^2}{32}\) - \(\frac{1}{4}\)
3
\(\frac{\pi^2}{32}\) - \(\frac{1}{8}\)
4
\(\frac{\pi^2}{32}\) + \(\frac{1}{8}\)

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