defence exam Agniveer Vayu Group X & XY Mock Test 01/2026 Mathematics Differential Calculus Evaluation of derivatives
The derivative of \(\tan ^{-1}\left(\frac{\sqrt{1+x^2}-1}{x}\right)\) with respect to tan-1x is:
1
\(\frac{\sqrt{1+x^2}-1}{x^2}\)
2
\(\frac{1}{2}\)
3
1
4
\(\frac{1}{1+x^2}\)