The equation of  tangent to the curve \(x=\dfrac{2at^2}{1+t^2}, y=\dfrac{2at^3}{1+t^2}\) at the point for which \(t=\dfrac{1}{2}\), is

1
13x - 16y = 2a
2
13x + 16y = 2a
3
13x - 8y = 4a
4
13x + 8y = 4a

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