If \(y=\sin ^{-1}\left(\frac{5 x+12 \sqrt{1-x^{2}}}{13}\right) \text { then } \frac{d y}{d x}\) equals

1
\(\frac{-2 x}{\sqrt{1-x^{2}}}\)
2
\(\frac{-1}{\sqrt{1+x^{2}}}\)
3
\(\frac{1}{\sqrt{1-x^{2}}}\)
4
\(\frac{2 x}{\sqrt{1-x^{2}}}\)

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