If x = \(\sqrt{10^{\sin ^{-1} t}}\), y = \(\sqrt{10^{\cos ^{-1} t}}\) then \(\frac{d y}{d x}\) = _______.

1
\(-\frac{x}{y}\)
2
\(\frac{y}{x}\)
3
0
4
\(-\frac{y}{x}\)

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