If the value of \(\frac{3 \cos 36^{\circ}+5 \sin 18^{\circ}}{5 \cos 36^{\circ}-3 \sin 18^{\circ}}\) is \(\frac{a \sqrt{5}-b}{c}\), where a, b, c are natural numbers and gcd(a, c) = 1, then a + b + c is equal to :

1
50
2
40
3
52
4
54

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