Let f ∶ [0, 1] → [0, 1] be defined by f(x) = \(\left\{\begin{array}{c}x, \text { if } x \text { is rational } \\ 1−x, \text { if } x \text { is irrational }\end{array}\right.\)

Then (f o f) x is

1
constant
2
1 + x
3
x
4
none of these

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