Consider the 4–to–1 multiplexer with two lines S1 and S0 given below:

The minimal sum of – products form of the Boolean expression for the output F of the multiplexer is

1
\(\bar ABC + A\bar B\bar C+ AB\)
2
\(A\bar C + \bar BC\)
3
\(A + B + C\)
4
\(A ⊕ B ⊕ C\)

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