Consider a signal defined by

\(x\left( t \right) = \left\{ {\begin{array}{*{20}{c}} {{e^{~j10t}}}&{for\left| t \right| \le 1}\\ 0&{for\left| t \right| > 1} \end{array}} \right.\)

Its Fourier Transform is

1
\(\frac{{2\sin \left( {\omega - 10} \right)}}{{\omega - 10}}\)
2
\(\frac{{2{e^{j10}}\sin \left( {\omega - 10} \right)}}{{\omega - 10}}\)
3
\(\frac{{2sin\omega }}{{\omega - 10}}\)
4
\(\frac{{{e^{j10\omega }}2sin\omega }}{\omega }\)

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