Laplace transform of x(t) is given as X(s) = 3s2 + 2s + 1, this signal x(t) is subjected to an unknown operation after which Laplace transform becomes X1(s) = 6s + 2, the new version of Laplace inverse x1(t) is:
1
\({x_1}\left( t \right) = \frac{{dx\left( t \right)}}{{dt}}\)
2
x1(t) = ∫ x(t) ⋅ dt
3
x1(t) = -tx(t)
4
x1(t) = (-1/t)x(t)