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With K as a constant, the possible solution for the first order differential equation \(\frac{dy}{dx}=e^{-3x}\) is
1
\(-\frac{1}{3}e^{-3x}+K\)
2
\(-\frac{1}{3}e^{3x}+K\)
3
-3 e-3x + K
4
-3 e-x + K