The rate of heat transfer between an electric motor and its surroundings is given by Q = ln(t) + 2 Where t is in seconds and Q is in kW. The shaft of the motor rotates at a speed of 100 rad/s and applies a torque of 50 N-m on the load. The motor draws a constant electric power input of 4 kW. The time rate of change of energy (kW) of the motor is given by :

1
 ln(t) 
2
 ln(t) + 1
3
 ln(t) + 2
4
 ln(t) + 3

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