If \(\rm \displaystyle\int_0^{\pi/2}\log \cos x \ dx=\dfrac{\pi}{2}\log \left(\dfrac{1}{2}\right)\) then \(\rm \displaystyle\int_0^{\pi/2}\log \sec x \ dx = \)

1
\(\rm \dfrac{\pi}{2}\log \left( {}^{1}\!\!\diagup\!\!{}_{2} \right)\)
2
\(\rm 1 - \dfrac{\pi}{2}\log \left(\dfrac{1}{2}\right)\)
3
\(\rm 1 + \dfrac{\pi}{2}\log \left(\dfrac{1}{2}\right)\)
4
\(\dfrac{\pi}{2}\log 2\)

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