The diode cut-in voltage is 0.6 and the voltage drop across the conducting diode is 0.7 V. If V­1 = 10 V and V2 = 0 V then:

1
V0 = 0.7 V
2
V0 = 8.37 V 
3
V0 = 3.87 V
4
V0 = 4.07 V

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