How much torque will be produced by the armature of a DC shunt machine if the machine generates 10,000 W of mechanical power in the armature and rotates at the speed of 1500 revolutions per minute?
1
\( \frac{200}{\pi} \mathrm{N}-\mathrm{m} \)
2
\(\frac{20}{\pi} \mathrm{N}-\mathrm{m} \)
3
\( \frac{2}{\pi} \mathrm{N}-\mathrm{m}\)
4
0 N - m