The distance between the parallel planes 3x + y + 3z = 8 and 6x + 2y + 6z = 10 is:

1
\(\frac{3}{\sqrt19}\)
2
\(\frac{2}{\sqrt19}\)
3
\(\frac{5}{\sqrt19}\)
4
\(\frac{13}{\sqrt19}\)

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