If D and d are external and internal diameters of a circular shaft respectively, its polar moment of inertia is

1
\(\frac{\pi(D^4-d^4)}{2}\)
2
\(\frac{\pi(D^4-d^4)}{4}\)
3
\(\frac{\pi(D^4-d^4)}{64}\)
4
\(\frac{\pi(D^4-d^4)}{32}\)
5
\(\frac{\pi(D^4-d^4)}{16}\)

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