If (21x + 5)3 + (4 - x)3 - 64(7x - 5)3 = 12(21x + 5)(x - 4)(7x - 5), then what is the value of \(\sqrt{x^2+6}\) ?

1
\(\frac{35}{4\sqrt2}\)
2
\(\frac{45}{4\sqrt2}\)
3
\(\frac{25}{4\sqrt2}\)
4
\(\frac{35}{8}\)

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