Given the ordinary differential equation \(\frac{{{d^2}y}}{{d{x^2}}} + \frac{{dy}}{{dx}} - 6y = 0\) With y (0) = 0 and \(\frac{{dy}}{{dx}}\left( 0 \right) = 1\), the value of y(1) is ______ (correct to two decimal places).

Enter numerical value using the virtual keypad. Round off where necessary.

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