If 2x – y = 2 and xy = \(\frac{3}{2}\), then what is the value of x3 – \(\frac{{{y^3}}}{8}\)?

1
\(\frac{5}{2}\)
2
\(\frac{13}{4}\)
3
\(\frac{9}{2}\)
4
\(-\frac{5}{4}\)

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