A continuous time LTI system is described by

\(\dfrac{d^2y(t)}{dt^2} + 4 \dfrac{dy(t)}{dt} + 3y(t) = 2 \dfrac{dx(t)}{dt} + 4x(t)\)

Assuming zero initial conditions, the response y(t) of the above system for the input x(t) = e-2t u(t) is given by

1
(et - e3t) u(t)
2
(e-t - e-3t​) u(t)
3
(e-t + e-3t​) u(t)
4
(et + e3t) u(t)

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