The position of a particle (𝑑) is described by the differential equation:

\(\frac{{{{\rm{d}}^2}{\rm{y}}}}{{{\rm{d}}{{\rm{t}}^2}}} = - \frac{{{\rm{dy}}}}{{{\rm{dt}}}} - \frac{{5{\rm{y}}}}{4}\)

The initial conditions are y(0) = 1 and \({\left. {\frac{{{\rm{dy}}}}{{{\rm{dt}}}}} \right|_{{\rm{t}} = 0}} = 0\). The position (accurate to two decimal places) of the particle at t = π is _______.

Enter numerical value using the virtual keypad. Round off where necessary.

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