Consider the NMOS circuit shown
The drain to source voltage is VDS = (Vt + 2) volts, then drain current iD is:
\(\left( Assume~{{K}_{n}}={{\mu }_{n}}C_{ox}~\left( \frac{W}{L} \right) \right)\)1
iD = 2 Kn
2
iD = Kn
3
\({{i}_{D}}=\frac{{{K}_{n}}}{2}\)
4
\({{i}_{D}}=\frac{{{K}_{n}}}{4}\)