Find the general solution of \(\frac{{dy}}{{dx}} = {\left[ {\frac{{\left( {{e^x} - 1} \right){{\sec }^2}y}}{{{e^x}\tan y}}} \right]^{ - 1}}\) 

1
ex = c tan y + 1
2
sin y = c (1 - ex)
3
ex cos y = 1
4
cot y = 1 + ex

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