For the circuit shown below v(t) = 10e-4t V and i(t) = 0.2e-4t A, then the time in (ms) taken by capacitor to dissipate 50% of its initial energy is:
Enter numerical value using the virtual keypad. Round off where necessary.
For the circuit shown below v(t) = 10e-4t V and i(t) = 0.2e-4t A, then the time in (ms) taken by capacitor to dissipate 50% of its initial energy is:
Enter numerical value using the virtual keypad. Round off where necessary.