A continuous beam ABCD has end A as fixed and support B and C are simple supports while end D is free. The fixed end moments for beam AB are FEMAB = - 19.2 kNm and FEMBA =28.8 kNm. The moment equation for slope deflection method for beam AB can be written as:

1
\(M_{AB}=\frac{2EI}{L}(2\theta _{A}+\theta _{B})+28.8,\;M_{BA}=\frac{2EI}{L}(\theta _{A}+2\theta _{B})+19.2 \)
2
\(M_{AB}=\frac{2EI}{L}(\theta _{A})-19.2,\;M_{BA}=\frac{4EI}{L}(\theta _{A})+28.8 \)
3
\(M_{AB}=\frac{4EI}{L}(\theta _{A})-19.2,\;M_{BA}=\frac{2EI}{L}(\theta _{A})+28.8 \)
4
\(M_{AB}=\frac{2EI}{L}(\theta _{B})-19.2,\;M_{BA}=\frac{4EI}{L}(\theta _{B})+28.8 \)

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