In the Taylor series expansion of \(f\left( x \right) = {e^{2x}} + \left( {\frac{x}{{x + 2}}} \right)\) about x = 1, the coefficient of (x – 1)2 is

1
\({e^2} + \left( {\frac{4}{9}} \right)\)
2
\(4{e^2} - \left( {\frac{4}{9}} \right)\)
3
\({e^2} + \left( {\frac{4}{{27}}} \right)\)
4
\(2{e^2} - \left( {\frac{2}{{27}}} \right)\)

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