lf, m = mass of the ball of the governor, ω = angular velocity of the governor, g = acceleration due to gravity, then the height of Watt's governor is given by

1
\(\dfrac{g}{2\omega^2}\)
2
\(\dfrac{g}{\omega^2}\)
3
\(\dfrac{\sqrt{2g}}{\omega^2}\)
4
\(\dfrac{2g}{\omega^2}\)

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