The differential equation \(y'' - 6y' + 9y = \frac{{{e^{3x}}}}{{{x^2}}}\) is solving by the method of variation of parameters, where the complementary function is given by- y = c1y1(x) + c2y2(x)

1
The value of y1(x) = e3x
2
The value of ​y2(x) = e3x
3
The value of ​y2(x) = xe3x
4
\(W= \left| {\begin{array}{*{20}{c}} {{y_1}}&{{y_2}}\\ {y_1'}&{y_2'} \end{array}} \right| =e^{6x}\)

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