A parallel-plate capacitor with no dielectric has a capacitance of 0.5 μF. The space between the plates is then filled with equal amounts of two dielectrics of dielectric constants 2 and 3 in the two arrangements as shown. The ratio of capacitances of both the capacitances \(\frac{{{C_1}}}{{{C_2}}}\) is
1
\(\frac{1}{6}\)
2
\(\frac{25}{24}\)
3
\(\frac{24}{25}\)
4
6
5
\(\frac{12}{5}\)