If \(2x-\frac{1}{x}=7, x\ne0\), then what is the value of \(\frac{8x^6+5x^3-1}{8x^6-25x^3-1}\)?

1
\(\frac{39}{37}\)
2
\(\frac{19}{18}\)
3
\(-\frac{1}{5}\)
4
\(\frac{13}{12}\)

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