For a matrix [M] \(= \left[ {\begin{array}{*{20}{c}} {\frac{3}{5}}&{\frac{4}{5}}\\ x&{\frac{3}{5}} \end{array}} \right]\), the transpose of the matrix is equal to the inverse of the matrix [M]T = [M]-1. The value of x is given by

1
\(- \frac{4}{5}\)
2
\(- \frac{3}{5}\)
3
\(\frac{3}{5}\)
4
\(\frac{4}{5}\)

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