What will be the output of the following C program:(consider int is of 4 bytes and array (arr) starting address is 2000 in decimal )

#include

int main()

{

       int arr[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};

       printf("%u\n",(arr+1));

       printf("%u",(&arr + 1));

       return 0;

}