A particle is projected with velocity u at an inclination θ with the horizontal. Then Maximum height (H) attained is

1
\(\frac{u^2 sin^2\theta}{g}\)
2
\(\frac{2u^2 sin^2\theta}{g}\)
3
\(\frac{u^2 sin^2\theta}{2g}\)
4
\(\frac{u^2 sin2\theta}{g}\)
5
\(\frac{u^2 sin2\theta}{2g}\)

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