If f is the coefficient of friction, W is the unit weight of cement concrete in kg/m3, width and thickness of slab are b and h respectively in meter, As is the total area of steel in cm2 across the slab width and allowable tensile stress in steel in kg/cm2 is Ss, then what will be the spacing between contraction joints in meter (Lc)?
1
Lc= (b × h × W × f)/(200 Ss × As)
2
Lc = (200 Ss× As)/(b × h × W × f)
3
Lc = (200 b × h × W × f)/(Ss × As)
4
Lc = (Ss × As × b)/(200 hWf)