With initial condition x(1) = 0.5 , the solution of the differential equation \(t\frac{dx}{dt}+x=t\) is

1
\(x=t-\frac{1}{2}\)
2
\(x=t^2-\frac{1}{2}\)
3
\(x=\frac{t^2}{2}\)
4
\(x=\frac{t}{2}\)

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