The residue of function \(\rm f\left( z \right) = \frac{1}{{{z^4} - 8{z^2} + 16}}\) at \(\rm {z = 2}\) will be

1

\(\rm \frac{1}{16}\)

2

\(\rm \frac{-1}{32}\)

3

\(\rm \frac{-1}{16}\)

4

\(\rm \frac{1}{32}\)

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