The impedance of a circuit placed across a 120 V, 50 Hz source is (10 + j20) Ω. Find the current through the load. 

1
(2.4 + j4.8) A
2
(4.8 – j2.4) A
3
(4.8 + j2.4) A
4
(2.4 – j4.8) A

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