The discharge through a triangular notch is given by (with usual notations):
1
\(Q = \frac{2}{3}{C_d}\tan \frac{\theta }{2} \times \sqrt {2gH} \)
2
\(Q = \frac{8}{{15}}{C_d}\cdot \tan \frac{\theta }{2} \times \sqrt {2g} \cdot {H^{5/2}}\)
3
\(Q = \frac{2}{3}{C_d}\tan \frac{\theta }{2} \times \sqrt {2g} \cdot {H^{3/2}}\)
4
None of the above