The inverse Fourier transform of

\(X\left( \omega \right) = \frac{{j\omega }}{{{{\left( {2 + j\omega } \right)}^2}}}\) is

1
te-2tu(t)
2
(1 – t)e-2tu(t)
3
2te-2 tu(t)
4
(1 – 2t)e-2t u(t)

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