An open channel of symmetric right-angled triangular cross-section is conveying a discharge ā€˜Q’. Taking ā€˜g’ as the acceleration due to gravity, what is the critical depth?

1
\( {(\frac{Q^2}{g}}) ^{1/3}\)
2
\( {(\frac{Q^2}{g}}) ^{1/5}\)
3
\( {(\frac{2Q^2}{g}}) ^{1/5}\)
4
\( {(\frac{2Q^2}{g}}) ^{1/3}\)

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