A certain activity is given optimistic (tO), pessimistic (tP) & likely time (tL) estimates. Assuming the $\beta$ distribution for these time, the expected time (tE) for completing this activity is expressed as

1
t= (t+ 4 t+ tP)/6
2
t= (t- 4 t+ tP)/6
3
t= (t+ 6 t+ tP)/4
4
t= (t- 6 t+ tP)/4

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