Maximum pressure rise due to water hammer in a pipeline (a = area of the pipe; V0 = velocity, g = acceleration due to gravity; t = time period; L = length of the pipeline) is
1
\(\frac{{a{V_0}}}{{2g}}\)
2
\(\frac{{aV_0^2}}{{2g}}\)
3
\(\frac{{L{V_0}}}{{gT}}\)
4
Independent of the dimensions of the pipe