If \(f\left( x \right) = \frac{{x - 2}}{{x + 2}},\;x \ne - 2\), then what is f-1(x) equal to?

1
\(\frac{{4\left( {x + 2} \right)}}{{x - 2}}\)
2
\(\frac{{x + 2}}{{4\left( {x - 2} \right)}}\)
3
\(\frac{{x + 2}}{{x - 2}}\)
4
\(\frac{{2\left( {1 + x} \right)}}{{1 - x}}\)

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