One ticket is selected at random from 50 tickets numbered 00, 01, 02, ... ... 49. The probability that sum of the digits is 10, given that product of the digits is 9 is

1
\(\frac{9}{10}\)
2
\(\frac{1}{4}\)
3
\(\frac{1}{2}\)
4
\(\frac{2}{25}\)

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