If x = a(t - sin t) and y = a (1 - cos t) then \(\frac{d^2y}{dx^2}=\)

1
\(\frac{1}{{4a{{\sin }^4}\left( {\frac{t}{2}} \right)}}\)
2
\(\frac{-1}{{4a{{\sin }^4}\left( {\frac{t}{2}} \right)}}\)
3
\(\frac{1}{{4a{{\cos }^4}\left( {\frac{t}{2}} \right)}}\)
4
\(\frac{-1}{{4a{{\cos }^4}\left( {\frac{t}{2}} \right)}}\)

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