If two circles \({x^2} + {y^2} +4x - 2y + 4 = 0\) and \({x^2} + {y^2} - \alpha x - \frac{3}{2}y + 6 = 0\) intersect orthogonally then what will be the value of α.

1
\(\frac{3}{2}\)
2
\( - \frac{7}{4}\)
3
\( - \frac{{17}}{4}\)
4
\( - \frac{9}{4}\)

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