For the frame shown in figure the, the shear equation is
1
\(\frac{{({M_{BA}} + {M_{BC}})}}{4} + \frac{{{M_{CD}}}}{4} + P = 0\)
2
\(\frac{{({M_{BA}} + {M_{AB}})}}{4} + \frac{{{M_{CD}}}}{4} + P = 0\)
3
\({M_{BA}} + {M_{AB}} + {M_{CD}} + {M_{DC}} = 0\)
4
\({M_{BA}} + {M_{AB}} + {M_{CD}} + {M_{DC}} = P\)