Let ABCD be a parallelogram whose diagonals intersect at P and let O be the origin. What is \(\overrightarrow {{\rm{OA}}} + \overrightarrow {{\rm{OB}}} + \overrightarrow {{\rm{OC}}} + \overrightarrow {{\rm{OD}}}\) equal to?

1
\(2\;\overrightarrow {OP} \)
2
\(4\;\overrightarrow {OP}\)
3
\(6\;\overrightarrow {OP} \)
4
\(8\;\overrightarrow {OP} \)

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