If θ1 and θ2 are the angles of deviation from A to the top and bottom of a vertically held rod of length ‘S’ at B. The horizontal distance AB is (Both angles are on the same side)
1
\(\frac{S}{(tan \ \theta_1 - tan \ \theta_2)}\)
2
\(\frac{S}{(tan \ \theta_1 + tan \ \theta_2)}\)
3
\(\frac{S}{(tan \ \theta_2 - tan \ \theta_1)}\)
4
\(\frac{S}{(tan \ \theta_1 \times tan \ \theta_2)}\)